P^2+6p 16 =p^2+8p 2p 16 ∵ 16=8× ( 2) amp; 6=8 2 amp; =p(p+8) 2(p+8) =(p+8)(p 2) ...

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Factorisation by Regrouping Terms

Factorise: p2...

Question

Factorise:
$p^{2} + 6 p - 16$

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Solution

$p^{2} + 6 p - 16 = p^{2} + 8 p - 2 p - 16 {\begin{matrix} ∵ - 16 = 8 \times (- 2) 6 = 8 - 2 \end{matrix}} = p (p + 8) - 2 (p + 8) = (p + 8) (p - 2)$

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Factorise:
$p^{2} + 6 p + 8$

(i) p^{2} + 6 p + 8 (i i) p^{2} - 10 q + 21 (i i i) p^{2} + 6 p - 16

p^{2} + 6 p - 16

(1) p^{2} + 6 p + 8

(2) q^{2} - 10 q + 21

(3) p^{2} + 6 p - 16

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