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Question

Factorise the following:
$$a^2-12ab+36b^2-25$$.


A
(a+3b+5)(a+6b5)
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B
(a3b+5)(a6b5)
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C
(a+2b5)(a6b+5)
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D
(a6b+5)(a6b5)
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Solution

The correct option is D $$(a - 6b + 5)(a- 6b -5)$$
$$a^2-12ab+36b^2-25$$
$$=a^2-2\times a\times 6b+(6b)^2-5^2$$
$$=(a-6b)^2-5^2$$
$$=(a-6b+5)(a-6b-5)$$

Mathematics

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