Factorise the following:
$x^{3} + 8 y^{3} + 6 x^{2} y + 12 x y^{2}$

Open in App

Solution

$x^{3} + 8 y^{3} + 6 x^{2} y + 12 x y^{2}$
$= (x)^{3} + (2 y)^{3} + 3 (x) (2 y) [x + 2 y]$
$= (x + 2 y)^{3}$
$[∵ (a + b)^{3} = a^{3} + b^{3} + 3 a b (a + b)]$

Suggest Corrections

Similar questions

Find the cube of $x + 2 y$ .

x^{3} + 8 y^{3} + 6 x^{2} y + 12 x y^{2}

The value of $(x + 2 y)^{3}$ is _______.

x^{3} + 8 y^{3}

Join BYJU'S Learning Program