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Question

Factorise the given algebraic expression:
xypq+qypx

A
(py)(x+q)
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B
(yp)(x+q)
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C
(yp)(xq)
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D
(yx)(p+q)
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Solution

The correct option is B (yp)(x+q)
xypq+qypx
By suitably rearranging the terms, we get
(xypx)+(qypq)
=x(yp)+q(yp)
=(yp)(x+q)

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