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Question

Factorised form of 23xy−46x+54y−108 is

A
(23x+54)(y2)
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B
(23x+54y)(y2)
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C
(23xy+54y)(46x108)
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D
(23x+54)(y+2)
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Solution

The correct option is A (23x+54)(y2)
We have
23xy46x+54y108
Factoring out 23 from the first two terms and 54 from the last two,
=23x(y2)+54(y2)
Now, factoring out (y2),
=(23x+54)(y2)

23xy46x+54y108=(23x+54)(y2)

Hence, option (A) is correct.

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