Factorising $x^{2} + 16 x + 63$ we get, $(x + 7)$ and .

(x - 7) (x + 9)

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(x + 7) (x - 9)

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(x + 9)

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(x - 9)

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Solution

The correct option is C $(x + 9)$
Given: $x^{2} + 16 x + 63.$

Comparing the given expression with the identity $x^{2} + (a + b) x + a b$ we get, $a b = 63 a n d (a + b) = 16.$
$S o, (9 + 7) = 16 a n d (9) (7) = 63$

Hence,
$x^{2} + 16 x + 63$
$= x^{2} + 9 x + 7 x + 63$
$= x (x + 9) + 7 (x + 9)$
$= (x + 7) (x + 9)$

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