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Question

Factorization: (a+b)22(a2b2)+(ab)2


A
4b2
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B
4(ab)2
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C
4(a+b)2
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D
4a2
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Solution

The correct option is A 4b2
(a+b)22(a2b2)+(ab)2

(a+b)22(a+b)(ab)+(ab)2

Let x=(a+b),y=(ab)

x22xy+y2

(xy)2

Substituting the values of x and y,we get

((a+b)(ab))2

(a+ba+b)2

(2b)2

4b2

Mathematics

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