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Question

Factorize: 16(a+b)24a4b


Your Answer
A
4(a+b)(4a+4b+1)
Your Answer
B
4(a+b)(4a4b1)
Your Answer
C
16(a+b)(a+b1)
Correct Answer
D
4(a+b)(4a+4b1)

Solution

The correct option is D 4(a+b)(4a+4b1)
16(a+b)24a4b

16(a+b)24(a+b)

Take out 4(a+b) common, we get,

4(a+b)[4(a+b)1]

4(a+b)(4a+4b1)

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