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Question

Factorize: (3x2y)2+3(3x2y)10
  1. (3x+2y5)(3x2y+2)
  2. (3x2y+5)(3x2y2)
  3. (3x+2y+5)(3x+2y2)
  4. (3x2y5)(3x2y2)


Solution

The correct option is B (3x2y+5)(3x2y2)
(3x2y)2+3(3x2y)10
Let (3x2y)=a
a2+3a10
a2+5a2a10
a(a+5)2(a+5)
(a+5)(a2)
 Substituting a=(3x2y)
 (3x2y+5)(3x2y2)

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