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Question

Factorize each of the following algebraic expression:
a2 + 4b2 − 4ab − 4c2

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Solution

a2+4b2-4ab-4c2=(a2-4ab+4b2)-4c2=[a2-2×a×2b+(2b)2]-4c2=(a-2b)2-(2c)2=[(a-2b)-2c][(a-2b)+2c]=(a-2b-2c)(a-2b+2c)

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