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Question

Factorize:
(i) x2+5x+6=0
(ii) x25x+6=0
(iii)x2+5x6=0
(iv) x25x6=0

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Solution

(i) x2+5x+6=0 [using mid term expansion]
x2+3x+2x+6=0
x(x+3)+2(x+3)=0
(x+2)(x+3)=0
[x=2] & [x=3]

(ii) x25x+6=0 [using mid term expansion]
x23x2x+6=0
x(x3)2(x3)=0
(x2)(x3)=0
[x=2] & [x=3]

(iii) x2+5x6=0 [using mid term expansion]
x2x+6x6=0
x(x1)+6(x1)=0
(x+6)(x1)=0
[x=6] & [x=1]

(iv) x25x6=0 [using mid term expansion]
x2+x6x6=0
x(x+1)6(x+1)=0
(x6)(x+1)=0
[x=6] & [x=1]



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