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Question

Factorize the below equation:
(3x−2y)2+3(3x−2y)−10

A
(3x2y+5)(3x2y2)
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B
(x2y+5)(3x2y2)
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C
(3xy+5)(3xy2)
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D
(x2y+5)(xy2)
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Solution

The correct option is B (3x2y+5)(3x2y2)
(3x2y)2+3(3x2y)10
=(3x2y)2+5(3x2y)2(3x2y)10
=(3x2y)((3x2y)+5)2((3x2y)+5)
=((3x2y)+5)((3x2y)2)

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