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Question

Factorize the following:
$$(3x - 2y)^{2} + 3(3x - 2y) - 10$$


A
(3x2y5)(3x+2y+2)
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B
(3x8y+5)(x2y2)
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C
(3x2y+5)(3x2y2)
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D
(x2y+5)(3xy2)
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Solution

The correct option is B $$(3x - 2y + 5) (3x - 2y - 2)$$
   $$(3x - 2y)^{2} + 3(3x - 2y) - 10$$
$$=(3x - 2y)^{2} + 5(3x - 2y)-2(3x-2y)- 10$$
$$=(3x-2y)(3x-2y+5)-2(3x-2y+5)$$
$$=(3x-2y+5)(3x-2y-2)$$

Mathematics

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