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Question

Factorize - (x2)3729


Solution

(x2)3(9)3(x2)3((3)2)3a3b3=(ab)(a2+b2+ab)(x232)(x4+34+x232)a2b2=(a+b)(ab)(x+3)(x3)(x4+9x2+81)
So, final answer is (x+3)(x3)(x4+9x2+81).

 

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