Factorize- x-2-7x-12-x-3-x-4-x-3-x-4-x-3-x-4-x-3-x-4-

The correct option is A (x 3)(x 4)We have to break up 7x in the nbsp;given expression into two parts in such a way that their sum is 7x and the product of th ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Factorization of a Quadratic Trinomial

Factorize: x^...

Question

Factorize: $x^{2} - 7 x + 12$ .

(x - 3) (x - 4)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(x + 3) (x - 4)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x - 3) (x + 4)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x + 3) (x + 4)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $(x - 3) (x - 4)$
We have to break up $7 x$ in the given expression into two parts in such a way that their sum is $7 x$ and the product of their coefficients is $12$ .
$x^{2} - 7 x + 12$
$= x^{2} - 4 x - 3 x + 12$
$= x (x - 4) - 3 (x - 4)$
$= (x - 3) (x - 4)$

Thus, $x^{2} - 7 x + 12$ can be factorised as $(x - 3) (x - 4)$ .

Suggest Corrections

Similar questions

${lim}_{x \to - 2} \frac{x^{3} + x^{2} + 4 x + 12}{x^{2} - 3 x + 2}$

Q. Simplify

\frac{x}{x^{2} + 3 x - 4} + \frac{4 x}{x^{2} + 7 x + 12} .

Factorize : $x^{2} + 6 x + 8$

Q. Factorize:

(3 x + y)^{2} (4 x - 5) + x y (3 x + y)^{2} (4 x - 5) (x + 2 y)

$12 x - 3 x + 4 x - 3 x - 7 x$ equals ___ .

Join BYJU'S Learning Program

Factorize: x2−7x+12.

The correct option is A (x−3)(x−4)We have to break up 7x in the given expression into two parts in such a way that their sum is 7x and the product of their coefficients is 12. x2−7x+12 =x2−4x−3x+12 =x(x−4)−3(x−4) =(x−3)(x−4) Thus, x2−7x+12 can be factorised as (x−3)(x−4).

Factorize: $x^{2} - 7 x + 12$ .