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Question

Factorize:
x2+ax(6a25ab+b2).

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Solution

Now,
x2+ax(6a25ab+b2)
=x2+ax(6a23ab2ab+b2)
=x2+ax(3ab)(2ab)
=x2+{(3ab)(2ab)}x(3ab)(2ab)
=x(x+3ab)(2ab)(x+3ab)
=(x+3ab)(x2a+b)

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