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Question

Factors of 

x3125


  1. (x+5)(x25x+25)

  2. 1(x+5)(x25x+25)

  3. (x5)(x2+5x25)

  4. 1(x5)(x25x+25)


Solution

The correct option is B

1(x+5)(x25x+25)


x3125

Take 1 common from the expression, we get

1(x3+125)

=1(x3+53)

=1(x+5)(x25x+25)

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