Question

Father is aged three times more than his son Ronit. After $8$ years, he would be two and a half times of Ronit's age. After further $8$ years, how many times would he be of Ronit's age?

• A. $1$
• B. $\frac{3}{2}$
• C. $2$
• D. $\frac{5}{2}$

Answer 1

The correct option is C $2$

Let Ronit's present age be $x$ years.
Then, present age of father $=x+3x=4x$ years
$\therefore (4x+8)=\frac{5}{2}(x+8)$
$\Rightarrow 8x+16=5x+40$
$\Rightarrow x=8$
Hence, required ratio $=\frac{4x+16}{x+16}=\frac{48}{24}=2$