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Question

Fig shows a uniform rod of length 30 cm having a mass 3 kg. Calculate the force exerted by 20 cm part of the rod of 10 cm part.
1117857_11b9bfe0c47b4d6f966cae1aa5b7b55f.png

A
24 N
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B
48 N
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C
50 N
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D
None
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Solution

The correct option is A 24 N
Correct option is (A) As we know; Frut = Ma 3220=3 a 4 m/s2=a


Mass of 10 cm=330×10=1 kg so, T20=M10×aT20=4T=24 N

1996378_1117857_ans_6ee619ceec904ba5b7ea6fbd29cae8c2.png

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