CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Figure given in the question is a cross sectional view of a coaxial cable.The centre conductor is surrounded by a rubber layer,which is surrounded by an outer conductor,which is surrounded by another rubber layer.The current in the inner conductor is 1.0 A out of the page,and the current in the outer conductor is 3.0 A into the page.Determine the magnitude and direction of the magnetic field at points a and b.
215544_fe182c921d36493ab8dd67f6ab603c29.png

Open in App
Solution

Applying Ampere's circuit at law:
BA=μo2πiinr
=(2×107)(1)103=2×104T
This is due to () current of 1 A.Hence magnetic lines are circular and anticlockwise.Hence magnetic field is upwards.
Bb=μo2πiinr
=(2×107)(31)3×103=1.33×104T
This is due to net current. Hence magnetic lines are clockwise.
So, magnetic field at B is downwards.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Ampere's Law
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon