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Question

Figure gives a system of logic gates. From the study of truth table it can be found that to produce a high output (1) at R, we must have

A
X = 0, Y = 1
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B
X = 1, Y = 1
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C
X = 1, Y = 0
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D
X = 0, Y = 0
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Solution

The correct option is C X = 1, Y = 0


The truth table can be written as
XY¯¯¯¯¯X¯¯¯¯YP=¯¯¯¯¯X+YQ=¯¯¯¯¯¯¯¯¯¯¯X.¯¯¯¯YR=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯P+Q0110110110011010010010011110

Hence X=1, Y=0 gives output R=1


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