Question

Figure shows a rectangular loop conducting $$PQRS$$ in which the arm $$PQ$$ is free to move. A uniform magnetic field acts in the direction perpendicular to the plane of the loop. Arm $$PQ$$ is moved with the velocity $$v$$ towards the arm $$RS$$. Assuming that the arms $$QR, RS$$ and $$SP$$ have negligible resistance and the moving arm $$PQ$$ has the resistance $$r$$, obtain the expression forThe current in the loop

Solution

Current in the loop $$PQRS$$$$I=\dfrac{\varepsilon}{r}$$Since $$\varepsilon=\dfrac{d\varphi}{dt}=Blv$$ So, $$I=\dfrac{Blv}{r}$$Physics

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