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Question

Figure shows a square current-carrying loop ABCD of side 2 m and current I=12A. The magnetic moment M of the loop is:
1024893_088ead9c989141ada1aaf0bd3e5e7499.png

A
(^i3^k)Am2
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B
(^j^k)Am2
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C
(3^i^k)Am2
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D
(^i^k)Am2
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Solution

The correct option is A (^i3^k)Am2
DA=2cos30^i2sin30^k=(3^i^k)
AB=2^j
M=i(DA×AB)
=12](3^i^k)×(2^j)]
=3^k+i
=(i3^k) Am2

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