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Question

Figure shows graph of stopping potential V0 vs. frequency f for two metal surfaces A and B respectively, then 


Your Answer
A
θB>θA
Correct Answer
B
ϕB>ϕA  [ϕ is magnitude of  work function of metal]
Correct Answer
C
θA=θB
Your Answer
D
ϕA>ϕB

Solution

The correct options are
B ϕB>ϕA  [ϕ is magnitude of  work function of metal]
C θA=θB
Stopping voltage V0 is eV0=hfϕ

V0=h feϕe, where he is slope which is constant, so θA=θB

Also, from the graph, the magnitude of y intercept of B is more than A. So, 
ϕB>ϕA.

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