Question

Figure shows the force-displacement graph for a moving body. What is the work done by the force in displacing body from $x=0$ to $x=35m$?

Answer 1

The area under the force-displacement graph gives the work done.

Let the area of the trapezium is $A_1$ and the area of the triangle from $35m$ to $40m$ is $A_2$.

The area from $0m$ to $35m$ is given as,

$A=A_1-A_2$

$=\frac{1}{2}\times 10\times \left(20+40\right)-\frac{1}{2}\times 5\times 5$

$=287.5$

Thus, the work done by the force is $287.5J$.