Question

# Figure shows two bulbs B$$_1$$ and B$$_2$$, resistor R and inductor L. When the switch S is turned off

A
both B1 and B2 die out promptly
B
both B1 and B2 die out with some delay
C
B2 die out promptly but B1 with some delay
D
B1 die out promptly but B2 with some delay

Solution

## The correct option is C B$$_1$$ die out promptly but B$$_2$$ with some delayIn the given diagram, bulb $$B_{2}$$ and inductor $$L$$ constitute a series $$LR$$ circuit. When the switch S is turned off, current decreases in this $$LR$$ circuit, but does not becomes zero rapidly, because due to change in current, magnetic flux linked with inductor coil, changes and as a result an  emf is induced in inductor, which opposes the decrease in current due to Lenz's law, therefore current does not become zero rapidly and bulb $$B_{2}$$ dies out with some delay.On the other hand bulb $$B_{1}$$ and resistance R, constitute a simple R circuit , in which as the voltage becomes zero, current becomes zero and $$B_{1}$$ dies out promptly.PhysicsNCERTStandard XII

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