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Question

Figure shows two bulbs B$$_1$$ and B$$_2$$, resistor R and inductor L. When the switch S is turned off
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A
both B1 and B2 die out promptly
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B
both B1 and B2 die out with some delay
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C
B2 die out promptly but B1 with some delay
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D
B1 die out promptly but B2 with some delay
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Solution

The correct option is C B$$_1$$ die out promptly but B$$_2$$ with some delay
In the given diagram, bulb $$B_{2}$$ and inductor $$L$$ constitute a series $$LR $$ circuit. When the switch S is turned off, current decreases in this $$LR$$ circuit, but does not becomes zero rapidly, because due to change in current, magnetic flux linked with inductor coil, changes and as a result an  emf is induced in inductor, which opposes the decrease in current due to Lenz's law, therefore current does not become zero rapidly and bulb $$B_{2}$$ dies out with some delay.
On the other hand bulb $$B_{1}$$ and resistance R, constitute a simple R circuit , in which as the voltage becomes zero, current becomes zero and $$B_{1}$$ dies out promptly.

Physics
NCERT
Standard XII

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