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Question

Figure shows two processes a and b for a given sample of a gas. If ΔQ1,ΔQ2 are the amounts of heat absorbed by the system in the two cases and ΔU1,ΔU2 are changes in internal energies respectively, then


  1. ΔQ1>ΔQ2; ΔU1>ΔU2
  2. ΔQ1<ΔQ2; ΔU1<ΔU2
  3. ΔQ1>ΔQ2; ΔU1=ΔU2.
  4. ΔQ1=ΔQ2; ΔU1=ΔU2


Solution

The correct option is C ΔQ1>ΔQ2; ΔU1=ΔU2.
From indicator diagram 

Initial and final states of the two processes a and b are same. 
So, ΔUa=ΔUb
From 1st law of thermodynamics,
For process a : ΔQ1=ΔU1+ΔW1
For process b : ΔQ2=ΔU2+ΔW2
Since, area under curve a > Area under curve b 
We get ΔW1>ΔW2
ΔQ1>ΔQ2
Therefore force we can conclude that (ΔU1)=(ΔU2) and (ΔQ1)>(ΔQ2)

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