Question

Fill in the blanks:

(viii) $8\times -4x{y}^2\times 3x^3{y}^2=\underset{–}{}$

Answer 1

To find: $8\times -4x{y}^2\times 3x^3{y}^2$

The multiplication of monomials can be performed by multiplication of their coefficients and literals.

$\therefore 8\times -4x{y}^2\times 3x^3{y}^2$
$=(8\times -4\times 3)\times (x{y}^2\times x^3{y}^2)$
$=(-96)\times x^{1+3}\times y^{2+2}$
$=-96x^4{y}^4$

Hence, $8\times -4x{y}^2\times 3x^3{y}^2=-96x^4{y}^4.$