Fill the blank spaces- - - 37 - - - 38

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Standard VIII

Mathematics

Commutative Property of Rational Numbers

Fill the blan...

Question

Fill the blank spaces: $. . . . . . . + \frac{3}{7} = . . . . . . + \frac{3}{8}$

\frac{3}{7}, \frac{3}{8}

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\frac{3}{8}, \frac{3}{7}

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\frac{8}{3}, \frac{8}{7}

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\frac{8}{3}, \frac{7}{3}

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Solution

The correct option is B $\frac{3}{8}, \frac{3}{7}$
Addition is commutative for rational numbers. i.e. $a + b = b + a$
$∴ \frac{3}{8} + \frac{3}{7} = \frac{3}{7} + \frac{3}{8}$
$∴$ The missing terms are $\frac{3}{8}, \frac{3}{7}$

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Similar questions

Q. Fill in the blanks with the suitable value:

\frac{19}{- 5} + [\frac{- 3}{11} + \frac{- 7}{8}] = [\frac{19}{- 5} + - -- -] + \frac{- 7}{8}

Q. In the given series
1, 8, 3, 5, 1, 3, 7, 8, 1, 5, 7, 3, 5, 8, 3, 1, 5, 3, 7, 1, 8, 3, 5, 3, 7, 8, 3, 5, 1, 7, 3, 7, 5, 1, 8, 3, 1, 7, 1, 8, 3, 8, 5, 1

How many times do the two consecutive (i.e. numbers one after the other) have a difference of

4

In the given series

1, 8, 3, 5, 1, 3, 7, 8, 1, 5, 7, 3, 5, 8, 3, 1, 5, 3, 7, 1, 8, 3, 5, 3, 7, 8, 3, 5, 1, 7, 3, 7,

5, 1, 8, 3, 1, 7, 1, 8, 3, 8, 5, 1

How many times the two consecutive numbers (i.e. numbers one after the other) are such that the first is

4

more than the second?

$Name the multiplication property of rational numbers shown below: (i) \frac{3}{5} \times \frac{- 8}{9} = \frac{- 8}{9} \times \frac{3}{5} (i i) \frac{- 3}{4} \times (\frac{5}{7} \times \frac{- 8}{15}) = (\frac{- 3}{5} \times \frac{5}{7}) \times \frac{- 8}{15} (i i i) \frac{4}{5} \times (\frac{3}{- 8} + \frac{- 4}{7}) = \frac{4}{5} \times \frac{3}{- 8} + \frac{4}{5} \times \frac{- 4}{7} (i v) \frac{- 7}{5} \times \frac{5}{- 7} = 1 (v) \frac{8}{- 9} \times 1 = 1 \times \frac{8}{- 9} = \frac{8}{- 9} (v i) \frac{- 3}{4} \times 0 = 0$

Q. Fill the blank space:

(- 8) \times . . . . . . = 3 \times . . . . . .

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Fill the blank spaces: .......+37=......+38

The correct option is B 38,37Addition is commutative for rational numbers. i.e. a+b=b+a∴38+37=37+38∴ The missing terms are 38,37

Fill the blank spaces: $. . . . . . . + \frac{3}{7} = . . . . . . + \frac{3}{8}$

The correct option is B $\frac{3}{8}, \frac{3}{7}$
Addition is commutative for rational numbers. i.e. $a + b = b + a$
$∴ \frac{3}{8} + \frac{3}{7} = \frac{3}{7} + \frac{3}{8}$
$∴$ The missing terms are $\frac{3}{8}, \frac{3}{7}$