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Question

Find a positive value of m for which the coefficient of x2 in the expression (1+x)m is 6. 


Solution

Here coefficient of x2 in (1+x)m=mC2=6

m(m1)2=6

m2m=12

m2m12=0

m24m+3m12=0

m(m4)+3(m4)=0

(m4)(m+3)=0

Either m-4=0 or m+3=0 

m=4 or m=3

So positive value of m is 4. 

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