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Question

Find a relation between x and y such that the point (x,y) is equidistant from (7,1) and (3,5)

A
xy=2
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B
x+y=2
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C
xy=3
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D
x+y=3
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Solution

The correct option is A xy=2

Distance between two points (x1,y1) and (x2,y2) can be calculated using the formula (x2x1)2+(y2y1)2
Given,
Distance between the points (x,y);(7,1)= Distance between (x,y);(3,5)


(7x)2+(1y)2=(3x)2+(5y)2


(7x)2+(1y)2=(3x)2+(5y)2

On expanding the squares and simplifying, we get

xy=2


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