Find a relation between x and y such that the point (x,y) is equidistant from (7,1) and (3,5)
Distance between two points (x1,y1) and (x2,y2) can be calculated using the formula √(x2−x1)2+(y2−y1)2
Given, Distance between the points (x,y);(7,1)= Distance between (x,y);(3,5)
√(7−x)2+(1−y)2=√(3−x)2+(5−y)2
⇒(7−x)2+(1−y)2=(3−x)2+(5−y)2
On expanding the squares and simplifying, we get
x−y=2