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Question 10
Find a relation between x and y such that the point (x, y) is equidistant from the point (3, 6) and (- 3, 4).


Solution

Point (x, y) is equidistant from (3, 6) and ( - 3, 4).
And Distance between the points is given by
(x1x2)2+(y1y2)2
(x3)2+(y6)2=(x(3))2+(y4)2
(x3)2+(y6)2=(x+3)2+(y4)2
(x3)2+(y6)2=(x+3)2+(y4)2
x2+96x+y2+3612y=x2+9+6x+y2+168y
3616=6x+6x+12y8y
20=12x+4y
3x+y=5
3x+y5=0

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