Find an integer a such that
(i) a + 6 = 0
(ii) 5 + a = 0
(iii) a + (−4) = 0
(iv) −8 + a = 0

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Solution

(i) a + 6 = 0
=> a = 0 − 6
=> a = − 6

(ii) 5 + a = 0
=> a = 0 − 5

(iii) a + (−4) = 0
=> a = 0 − (−4)
=> a = 4

(iv) −8 + a = 0
=> a = 0 + 8
=> a = 8

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Find the nature of the roots of the following quadratic equations:
(i) $2 x^{2} - 8 x + 5 = 0$

(ii) $3 x^{2} - 2 \sqrt{6} x + 2 = 0$
(iii) $5 x^{2} - 4 x + 1 = 0$

(iv) $5 x (x - 2) + 6 = 0$
(v) $12 x^{2} - 4 \sqrt{15} x + 5 = 0$

(vi) $x^{2} - x + 2 = 0$

2 x^{2} - 8 x + 5 = 0

3 x^{2} - 2 \sqrt{6} x + 2 = 0

5 x^{2} - 4 x + 1 = 0

5 x (x - 2) + 6 = 0

12 x^{2} - 4 \sqrt{15} x + 5 = 0

x^{2} - x + 2 = 0

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