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Question

Find angle between the vectors a=^i+^j^k and ^b=^i+^j+^k.

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Solution

given a=^i+^j^k,b=^i+^j+^k
cosθ=a.bab=(^i+^j^k).(^i+^j+^k)^i+^j^k^i+^j+^k
=1+113.3=13
θ=cos1(13)

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