Find $∠ O P R$ if $∠ P O R = 30$ and $∠ O R P = 45$ in triangle $P Q R$

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Solution

IN $Δ P Q R$
Sum of all angles is $180^{\circ}$
$∠ P + ∠ Q + ∠ R = 180^{c i r c} ∠ p + 30 + 45 = 180 ∠ O P R = 180 - 75 = 105^{\circ}$

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