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Byju's Answer
Standard XII
Mathematics
Addition of Vectors
Find by vecto...
Question
Find by vector method the perimeter of the triangle whose vectors are
(
−
1
,
−
1
,
9
)
,
(
3
,
1
,
5
)
and
(
0
,
−
5
,
1
)
.
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Solution
A
B
=
(
1
−
,
1
−
,
9
)
−
(
3
,
1
,
5
)
=
(
−
4
,
−
2
,
4
)
|
A
B
|
=
√
4
2
+
2
2
+
4
2
=
6
B
C
=
(
3
,
1
,
5
)
−
(
0
,
−
5
,
1
)
=
(
3
,
6
,
4
)
|
B
C
|
=
√
9
+
36
+
16
=
√
61
C
A
=
(
0
,
−
5
,
1
)
−
(
−
1
,
−
1
,
9
)
=
(
1
,
−
4
,
−
8
)
|
C
A
|
=
√
1
2
+
4
2
+
8
2
=
√
64
+
16
+
1
=
9
Perimeter
=
|
A
B
|
+
|
B
C
|
+
|
C
A
|
=
6
+
√
61
+
9
=
15
+
7.81
=
22.81
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