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Question

Find  $$\dfrac { d ^ { 2 } y } { d x ^ { 2 } } ,$$  if  $$y = \log x$$


Solution

$$\begin{array}{l} y=\log  x \\ \frac { { dy } }{ { dx } } =\frac { 1 }{ x }  \\ \frac { { { d^{ 2 } }y } }{ { d{ x^{ 2 } } } } =\frac { { -1 } }{ { { x^{ 2 } } } }  \end{array}$$

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