Find dydx of the given function yx -xy-

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Logarithmic Differentiation

Find dydx o...

Question

Find $\frac{d y}{d x}$ of the given function $y^{x} = x^{y} .$

y^{x} l o g y

y x^{(y - 1)}

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x^{y} l o g x

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x^{y} l o g y

y x^{(y - 1)}

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Solution

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Similar questions

x^{y} + y^{x} = a^{b}

\frac{d y}{d x} = - [\frac{y x^{y - 1} + y^{x} log y}{x^{y} log x + x y^{x - 1}}]

x^{y} = y^{x}

\frac{d y}{d x} = \frac{y (x log y - y)}{x (y log x - x)}

\frac{d y}{d x} = \frac{y (x log y - y)}{x (y log x - x)}

Find $\frac{d y}{d x}$ of the functions given in question.

$x^{y} + y^{x} = 1$

\frac{d y}{d x}

x^{y} + y^{x} = 1

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