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Question

Find dydx when y=1+sin2xcos2x1+sin2x+cos2x.

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Solution

y=1+sin2xcos2x1+sin2x+cos2x
y=1+2sinxcosx1+2sin2x1+2sinxcosx+2cos2x1
y=2sinx(cosx+sinx)2cosx(sinx+cosx)
y=tanx
dy/dx=sec2x


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