Find: $\frac{sec 52^{o}}{c o s e c 38^{o}}$ .

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Solution

$\frac{sec 52^{\circ}}{c o s e c 38^{\circ}}$
$\frac{sin 38^{\circ}}{cos 52^{\circ}} = \frac{sin 38^{\circ}}{sin (90 - 52)} = 1$

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\frac{sec 52^{o}}{c o s e c 38^{o}}

cot 12^{o} . cot 38^{o} . cot 52^{o} . cot 60^{o} . cot 78^{o}

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∠

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∠

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