Question

Find each angle of a pentagon if its angles are in the ratio of $1:2:3:5:9$

Answer 1

Sum of all the angles of a pentagon$={540}^0$

Let the angles be $x,2x,3x,5x$ and $,9x$

$x+2x+3x+5x+9x={540}^0$

$20x={540}^0$

$x={27}^0$

Angles are ${27}^0,{54}^0,{81}^0,{135}^0,$ and ${243}^0$