Question

# Find equivalent resistance between A & B in the circuit is 8.5 Ω 16.5 Ω 49 Ω 18 Ω

Solution

## The correct option is B 16.5 Ω Since 12Ω & 18Ω are in series & we know, For series connection, Req=R1 +R2 +R3 +........ +Rn  ∴ We can substitute (12Ω + 18Ω) as 30Ω. Now, 30Ω & 10Ω are in parallel & we know, For parallel 1Req= 1R1 +1R2 +1R3+........ +1Rn ∴ 1R= 130 +110= (1+330)1R= 430R= 304= 7.5 Now 9Ω & 7.5Ω are in series & we know, for series Req=R1 +R2 +R3 +........ +Rn ∴Req= 9+7.5= 16.5

Suggest corrections