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Byju's Answer
Standard XII
Mathematics
Law of Reciprocal
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Question
Find graphical solution for the following system of linear in equation:
3
x
+
4
y
≤
12
,
x
−
2
y
≥
2
,
y
≥
−
1
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Solution
Ref. image 1
First we draw the lines AB,CD and ED whose equations are 3x + 4y = 12, x - 2y = 2 and y = -1 respectively.
Ref. image 2
The solution set of given system of inequation is shaded in the graph.
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Q.
Show that the following system of linear equations has no solution:
x
+
2
y
≤
3
,
3
x
+
4
y
≥
12
,
x
≥
0
,
y
≥
1