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Question

Find $$HCF$$ and $$LCM$$ of $$404$$ and $$96$$ and verify that $$HCF\times LCM=$$ product of the two given numbers.


Solution

Let $$a=404$$ and $$b=96$$
Expressing the number as a product of prime number
$$404=2\times 2\times 101$$
$$96=2\times 2\times 2\times 2\times 2\times 3$$
$$\therefore$$ LCM of 404 and 96 is $$2\times 2\times 2\times 2\times 2\times 101\times 3=9696$$
$$\therefore$$ HCF of 404 and 96 is $$2\times 2=4$$
Now,  $$HCF\times LCM=4\times 9696=38784$$
Product of two given numbers $$404\times 96=38784$$
Hence $$HCM\times LCM=$$ Product of two given numbers.

Maths

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