Find limx→3f(x), where
f(x)={4,ifx>3x+1,ifx<3
limx→3+f(x)=4
Now, limx→3−f(x)=limx→3−(x+1)
Put x =3 -h
⇒h=3−x
as x→3−⇒x<3 slightly
⇒h→0+
limx→0+(3−h+1)=3+1=4
Since, limx→3+f(x)=4=limx→3−f(x)
∴limx→3f(x)=4.
Find
limx→1 f(x) where f(x)= {x2−1,x≤1−x2−1x>1
Find limx→0 f(x) where f(x) = {x|x|x≠00x≠0