Find maximum and minimum values of following function,, if exists: (d) sin 2x+5
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Solution
(d) Let h(x)=sin2x+5 sin (2x) has maximum value as 1 So, h(x) has maximum value as 1+5=6 Again, sin (2x) has minimum value as −1 So, minimum value of h(x) will be −1+5=4