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Question

Find out the value of K_c for each of the following equilibria from the value of Kp:
(i) 2NOCl(g)2NO(g)+Cl2(g):     Kp=1.8×102 at 500 K


Solution

The relation between Kp and Kc is given as:
Kp=Kc(RT)Δ n

(i) Here,
Δ n=32=1R=0.0831 bar Lmol1K1T=500 KKp=1.8×102
Now,
Kp=Kc(RT)Δ n1.8×102=Kc(0.0831×500)1Kc=1.8×1020.0831×500=4.38×104


Chemistry
NCERT Textbook
Standard XI

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