Find real values of x for which 27cos2x⋅81sin2x is minimum. Also find this minimum value.
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Solution
E=33cos2x+4sin2x Now, 3cos2x+4sin2x=rcos(2x−α) where 3=rcosα,4=rsinα i.e., r=5,tanα=4/3 Its minimum values is −r When cos(2x−α)=−1cosπ or 2x−α=2nπ±π ∴x=(2n±1)π2+12tan−143 and in this case min value of E is 3−r=3−5=1/243.