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Question

Find t11 from the given A.P. 4, 9, 14, ...

A
54
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B
55
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C
51
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D
21
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Solution

The correct option is C 54
Given series is 4,9,14,....
Clearly, the given sequence is an AP with first term a=4 and the common difference d=5.
We know, an=a+(n1)d
Now, t11=a+10d
t11=4+10×5=54

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