CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Find the $$12^{th}$$ term from the end of the A.P. : -2, -4, -6, ...., -100.


Solution

Main concept used: To find the term from end, consider the given A.P. in reverse order and find the term. i.e., -100.... -6, -4, -2. 
Now, a = -100
$$d=a_{n+1}-a_n=-4-(-6)=-4+ 6=2 $$
$$\therefore n = 12$$
 $$\Rightarrow  a_n = a + (n - 1)d $$
$$a_12 = -100 + (12 - 1) (2)$$
$$ = -100 + 11 \times  2 = -100 22$$
 $$\Rightarrow a_{12} = -78$$
 Hence, the 12th term from the last of A.P. -2, -4, -6, ...... -100 is -78.

Maths

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image